This is a text containing a schema for specifying a dialog quiz on a QuizComposer server. Click the links # for detailed instructions.
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Create_hyper_quiz_0_1 # |
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Display_MathML_0_1 # |
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For_regist_answerers_0_1 # |
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Page_head # |
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Heading # |
Example of a hyper quiz. |
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Introduction # |
This is an example of a quiz in which the answer to a question
determines which question should follow. |
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Intro_repeat_0_1 # |
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Qstn_name_number_1 # |
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Qstn_phrase_1 # |
A train, T1, leaves the station A making for station B at the
same time as another train, T2, leaves station B making for
station A. Both trains run at a steady speed, T1 at 125 km/h
(kilometers per hour), T2 at 145 km/h. The distance from station
to station is 375 km. |
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Correct_answer_1 # |
173.6+-0.01 |
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Hints_1 # |
3 Your answer was incorrect, consequently you'll get a little help. |
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Reward_1 # |
2 Right! You'll get a supplementary question. |
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Qstn_name_number_2 |
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Qstn_phrase_2 |
How long time (t) has passed when the trains pass each other (state the answer as a number with four significant digits): |
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Correct_answer_2 |
1.389+-0.001 |
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Hints_2 |
3 |
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Reward_2 |
0 Right! But if you were in doubt as to whether the answer would be correct, answer the question again, but incorrectly. |
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Qstn_name_number_3 |
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Qstn_phrase_3 |
Write a formula expression for the distance between the trains
at time t (before they pass each other): [20]. |
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Correct_answer_3 |
!qcmath 375 - (125 + 145)*t |
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Hints_3 |
4 You'll get an easier question. |
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Reward_3 |
5 |
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Qstn_name_number_4 |
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Qstn_phrase_4 |
How many kilometers has the train traveled after t hours? Answer with a formula expression (remember * for multiplication). |
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Correct_answer_4 |
!qcmath 125 * t |
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Hints_4 |
3 The correct answer is the product of 125 and t. Try again. |
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Reward_4 |
6 |
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Qstn_name_number_5 |
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Qstn_phrase_5 |
From the formula expression you can determine the time t, when the trains pass each other. State the value of t with four significant digits: [] |
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Correct_answer_5 |
1.389+-0.001 |
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Hints_5 |
5 The distance between the trains is obviously 0 when the trains pass each other, thus: 375 - (125 + 145)*t = 0, from which t can be computed. |
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Reward_5 |
1 We shall return to the first question. |
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Qstn_name_number_6 |
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Qstn_phrase_6 |
How far is the train T2 from the station A at time t: |
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Correct_answer_6 |
!qcmath 375 - 145*t |
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Hints_6 |
The correct answer is 375 – 145*t. |
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Reward_6 |
5 You should now be able to answer the previous question(s) correctly. |
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Qstn_name_number_8 |
8 |
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Qstn_name_number_9 |
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Qstn_name_number_10 |
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Specs_from_quiz # |
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Text_before_qstn_number # |
Question number |
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Text_after_qstn_number # |
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